F(x)=3x^2+4x+10

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Solution for F(x)=3x^2+4x+10 equation: 



(F)=3F^2+4F+10

We move all terms to the left:

(F)-(3F^2+4F+10)=0

We get rid of parentheses

-3F^2+F-4F-10=0

We add all the numbers together, and all the variables

-3F^2-3F-10=0

a = -3; b = -3; c = -10;
Δ = b2-4ac
Δ = -32-4·(-3)·(-10)
Δ = -111
Delta is less than zero, so there is no solution for the equation

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